From 956e0d50a9f0bea2752cc1a84ec26bc72416ce60 Mon Sep 17 00:00:00 2001 From: Haidong Ji Date: Sun, 9 Dec 2018 21:03:28 -0600 Subject: Organize lottery done! --- PlaygroundCpp/Sources/Playground.cpp | 128 ++++++++++++++++++++++------------- 1 file changed, 82 insertions(+), 46 deletions(-) diff --git a/PlaygroundCpp/Sources/Playground.cpp b/PlaygroundCpp/Sources/Playground.cpp index aff2024..dbb916c 100644 --- a/PlaygroundCpp/Sources/Playground.cpp +++ b/PlaygroundCpp/Sources/Playground.cpp @@ -1,61 +1,97 @@ -#include +#include #include +#include +#include //#include using std::vector; -long mergeInversionCount(vector &B, vector &C, vector &D) { - long count = 0; - while (B.size() != 0 && C.size() != 0) { - int b = B[0]; - int c = C[0]; - if (b <= c) { - D.push_back(b); - B.erase(B.begin()); - } else { - count += B.size(); - D.push_back(c); - C.erase(C.begin()); - } +struct Segment { + int start, end; + bool operator==(const Segment &s1) { + return (start == s1.start && end == s1.end); } - D.insert(D.end(), B.begin(), B.end()); - D.insert(D.end(), C.begin(), C.end()); - return count; +}; + +bool sortSeg(Segment i, Segment j) { + if (i.start == j.start) { + return i.end < j.end; + } + return i.start < j.start; } -long getInversionCountFromList(vector &A, vector &D) { - long numberOfInversions = 0; - if (A.size() == 1) { - D.push_back(A[0]); - return 0; +vector fast_count_segments(vector starts, vector ends, + vector points) { + // Implement algo described here, really clever: + // https://www.coursera.org/learn/algorithmic-toolbox/discussions/all/threads/QJ1jK9wNEeWdPBL2iFTrAw/replies/Ihiw4txhEeWK5g7mfcS2Xw/comments/oyAMaeIiEeWyqwpvChh66Q + // l->1, p->2, r->3 for Segment.end property + vector s(starts.size() + ends.size() + points.size()); + vector p(points.size()); + Segment tempSeg; + for (int i = 0; i < p.size(); i++) { + tempSeg = {points[i], i}; + p[i] = tempSeg; + tempSeg = {points[i], 2}; + s[2 * starts.size() + i] = tempSeg; + } + for (int i = 0; i < starts.size(); i++) { + tempSeg = {starts[i], 1}; + s[i] = tempSeg; + tempSeg = {ends[i], 3}; + s[i + starts.size()] = tempSeg; + } + std::sort(s.begin(), s.end(), sortSeg); + std::sort(p.begin(), p.end(), sortSeg); + vector results(points.size()); + int count = 0; + int j = 0; + for (int i = 0; i < s.size(); i++) { + if (s[i].end == 1) { + count = count + 1; + } + if (s[i].end == 2) { + results[j] = count; + j = j + 1; + } + if (s[i].end == 3) { + count = count - 1; + } + } + vector finalResults(points.size()); + for (int i = 0; i < finalResults.size(); i++) { + finalResults[p[i].end] = results[i]; } - int m = A.size() / 2; - vector D1; - vector::const_iterator first = A.begin(); - vector::const_iterator last = A.begin() + m; - vector newVec(first, last); - numberOfInversions += getInversionCountFromList(newVec, D1); - vector D2; - vector::const_iterator ffirst = A.begin() + m; - vector::const_iterator llast = A.end(); - vector newVecc(ffirst, llast); - numberOfInversions += getInversionCountFromList(newVecc, D2); - long mergeCount = mergeInversionCount(D1, D2, D); - return numberOfInversions + mergeCount; + return finalResults; } -//TEST(InversionCount, test1) { -// vector a = { 2, 3, 9, 2, 2 }; -// vector result(5); -// ASSERT_EQ(4, getInversionCountFromList(a, result)); +//TEST(SortSegment, Sort1) { +// vector starts = { 0, 7 }; +// vector ends = { 5, 10 }; +// vector points = { 1, 6, 11 }; +// vector results = { 1, 0, 0 }; +// +// vector cnt = fast_count_segments(starts, ends, points); +// +// ASSERT_EQ(cnt[0], 1); +// ASSERT_EQ(cnt[1], 0); +// ASSERT_EQ(cnt[2], 0); +// ASSERT_EQ(cnt.size(), 3); //} int main() { - int n; - std::cin >> n; - vector a(n); - for (size_t i = 0; i < a.size(); i++) { - std::cin >> a[i]; + int n, m; + std::cin >> n >> m; + vector starts(n), ends(n); + for (size_t i = 0; i < starts.size(); i++) { + std::cin >> starts[i] >> ends[i]; + } + vector points(m); + for (size_t i = 0; i < points.size(); i++) { + std::cin >> points[i]; + } + //use fast_count_segments + vector cnt = fast_count_segments(starts, ends, points); + for (size_t i = 0; i < cnt.size(); i++) { + std::cout << cnt[i] << ' '; } - vector b(a.size()); - std::cout << getInversionCountFromList(a, b) << '\n'; } + -- cgit v1.2.3