check if binary search tree harder version done!HEADmaster

Comparing this against my Java and Python code, one more change was
needed: key value type changed from int to long. In reality, I'm not
sure if int would have worked, but I decided to be better safe than
sorry.

1 files changed, 4 insertions, 4 deletions

diff --git a/Sources/DataStructure.cpp b/Sources/DataStructure.cpp
index ebb4c2e..e9332c4 100644
--- a/Sources/DataStructure.cpp
+++ b/Sources/DataStructure.cpp
@@ -13,7 +13,7 @@ using std::endl;
 class TreeOrders {
 public:
 	int n;
-	vector<int> key;
+	vector<long> key;
 	vector<int> left;
 	vector<int> right;
 
@@ -30,7 +30,7 @@ public:
 	bool is_Bst() {
 		if (key.size()==0) return true;
 		std::stack<int> keyIndexStack;
-		vector<int> result;
+		vector<long> result;
 		bool walkLeft = true;
 		int currentIndex = 0;
 		keyIndexStack.push(currentIndex);
@@ -44,14 +44,14 @@ public:
                     int i = keyIndexStack.top();
                     keyIndexStack.pop();
                     if (result.size() > 0) {
-                        if (key[i] <= result[(result.size()-1)]) return false;
+                        if (key[i] < result[(result.size()-1)]) return false;
                     }
                     result.push_back(key[i]);
                     walkLeft = false;
 				}
 			} else {
 				if (right[currentIndex] != -1) {
-                    if (key[right[currentIndex]] <= key[currentIndex]) return false;
+                    if (key[right[currentIndex]] < key[currentIndex]) return false;
 					currentIndex = right[currentIndex];
 					keyIndexStack.push(currentIndex);
 					walkLeft = true;